Python Compare two lists and return matches of same number in same order in a more pythonic way : looking for a more pythonic way for determining if the elements of my two lists are in the same order. I have sliced the two lists and turned the elements into d1 etc as below. Cant use sets only want to know if the Nth of list1 == Nth list2


    x = []
		if d1 == r1:
			print ('got one')
			x = x + 1
		if d2 == r2:
			print ('got one')
			x = x + 1
		if d3 == r3:
			print ('got one')
			x = x + 1
		if d4 == r4:
			print ('got one')
			x =x + 1