Extract string after a multiline string using python regex : <p>I have a string</p>

<pre><code>a='''S
LINC             SHORT LEGAL                                   TITLE NUMBER
0038 073 623     1522744;27                                    182 246 612 
+5

LEGAL DESCRIPTION
CONDOMINIUM PLAN 1522744  
UNIT 27  
AND 237 UNDIVIDED ONE TEN THOUSANDTH SHARES IN THE COMMON PROPERTY  
EXCEPTING THEREOUT ALL MINES AND MINERALS  

ESTATE: FEE SIMPLE  
ATS REFERENCE: 4;25;52;8;NW

MUNICIPALITY: CITY OF EDMONTON

REFERENCE NUMBER: 172 303 453 +7

---------------------------------------------------------------------------- 
----
         REGISTERED OWNER(S)
REGISTRATION    DATE(DMY)  DOCUMENT TYPE      VALUE           CONSIDERATION
---------------------------------------------------------------------------- 
----

182 246 612    01/10/2018  PHASED OF                           CASH &amp; MTGE
                           CONDOMINIUM PLAN                    '''
</code></pre>

<p>I need to get the string after the word 'PHASED OF CONDOMINIUM PLAN' which should returns 'CASH &amp; MTGE'
I have tried using the below expression</p>

<pre><code>date_value = (re.search(r'(\d+/\d+/\d+)', a)).group(1) //returns '01/10/2018'
doc_type = "".join(list(re.search(r"(?&lt;={})\s*((?:\S+\s)+).*\s*((?:\S+\s)+)".format(date_value),a).group(1, 2))).strip() //returns 'PHASED OF CONDOMINIUM PLAN' 
consideration = ((re.search(r"(?&lt;={}).*".format(doc_type),a)).group()).strip()
</code></pre>

<p>I could not get any match </p>
