Homework help - new programmer! Python calculating minimum max and average of a list : I'm new to python and my professor has not explained this assignment very well, many of my classmates are confused. He is an adjunct so he does not have office hours as well so I would be grateful for any sort of assistance or knowledge on how I can complete this. 

So, the prompt is "Write, debug, and test a program to calculate and print the minimum, maximum, and average of a list of positive test scores. Prompt the user for how many scores are to be entered.  Expect each score will be entered
one per line. Provide a prompt for each score."

So this what I currently have, but I'm stuck at finding the min, max, and avg. 

    def scores():
        print('we are starting')
        count = int(input('Enter amount of scores: '))
        print('Each will be entered one per line')
        scoreList = []
        for i in range(1, count+1):
                scoreList.append(int(input('Enter score: ')))
                print(scoreList)
        print(scoreList)
        print('thank you the results are:')
        mysum = sum(count)
        # mysum needs to be a float
        average = 1.0*mysum / n
        print ('Total: ', str(count))
        print ('Average: ', str(average))
        print ('Minimum: ', str(min(count)))
        print ('Maximum: ', str(max(count))) 
scores()

I'm not sure if it would be easier to do an elif type statement as I said I'm really new to this and I'm still just trying to understand whats going on in this code. 

next, I need to "expand the program to generate a score by grade table. For each rank of grade [A,B,C,D,F] the program counts the number of grades in the rank. The program prints a table of count by rank and provides the percentage of total grades in each rank. The ranks are as follows: A = 91 - 100   B = 81 - 90   C = 71 - 80   D = 61 - 70    F =  0 - 60"

I understand this is a lot, I would just appreciate some assistance or some input as any and all are very appreciated. Thanks in advance to anyone that responds and I will be updating if I get any further on this on my own.