Can anuone explain the below code How it works? : I have a custom class that has overridden hashcode() and equals() method


    class Employee1{
    private int id;
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public Employee1(int id) {
        super();
        this.id = id;
    }
    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + id;
        return result;
    }
    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        Employee1 other = (Employee1) obj;
        if (id != other.id)
            return false;
    
        return true;
    }
    
}


and in main class I am using a Map having Object as Key

    Map<Integer,Employee1> g = new HashMap<>();
        Employee1 e = new Employee1(1);
        Employee1 e1 = new Employee1(2);
        g.put(1, e);
        g.put(2, e1);
        Employee1 e4 = g.get(1);
        e4.setId(3);
        for(Map.Entry<Integer,Employee1> e3:g.entrySet()) {
           System.out.println(e3.getKey()+" "+e3.getValue().getId());
        }


my question is how come the key of the map is changed even though I have overridden hashcode and equals methods,key should be same but I am able to get and set the id and its  reflecting in the map

The o/p for above code is

1 3
2 2