For this Question: Given two strings s and t of lengths m and n respectively, Print the length of the minimum window substring of s such that every character in t (including duplicates) is included in the window. If there is no such substring, Print 0.The first line of the input contains the string s.
The next line of the input contains the string t.

Constraints
1 <= m, n <= 10<sup>5</sup>
s and t consist of uppercase and lowercase English letters.Print the length of minimum window substring.Sample Input 
ADOBECODEBANC
ABC

Sample Output 
BANC

Explanation
The minimum window substring "BANC" includes 'A', 'B', and 'C' from string t., I have written this Solution Code: /* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Main
{
    public static String minWindow(String s, String t) {

      if (s.length() == 0 || t.length() == 0) {
          return "";
      }

      // Dictionary which keeps a count of all the unique characters in t.
      Map<Character, Integer> dictT = new HashMap<Character, Integer>();
      for (int i = 0; i < t.length(); i++) {
          int count = dictT.getOrDefault(t.charAt(i), 0);
          dictT.put(t.charAt(i), count + 1);
      }

      // Number of unique characters in t, which need to be present in the desired window.
      int required = dictT.size();

      // Left and Right pointer
      int l = 0, r = 0;

      // formed is used to keep track of how many unique characters in t
      // are present in the current window in its desired frequency.
      // e.g. if t is "AABC" then the window must have two A's, one B and one C.
      // Thus formed would be = 3 when all these conditions are met.
      int formed = 0;

      // Dictionary which keeps a count of all the unique characters in the current window.
      Map<Character, Integer> windowCounts = new HashMap<Character, Integer>();

      // ans list of the form (window length, left, right)
      int[] ans = {-1, 0, 0};

      while (r < s.length()) {
          // Add one character from the right to the window
          char c = s.charAt(r);
          int count = windowCounts.getOrDefault(c, 0);
          windowCounts.put(c, count + 1);

          // If the frequency of the current character added equals to the
          // desired count in t then increment the formed count by 1.
          if (dictT.containsKey(c) && windowCounts.get(c).intValue() == dictT.get(c).intValue()) {
              formed++;
          }

          // Try and contract the window till the point where it ceases to be 'desirable'.
          while (l <= r && formed == required) {
              c = s.charAt(l);
              // Save the smallest window until now.
              if (ans[0] == -1 || r - l + 1 < ans[0]) {
                  ans[0] = r - l + 1;
                  ans[1] = l;
                  ans[2] = r;
              }

              // The character at the position pointed by the
              // `Left` pointer is no longer a part of the window.
              windowCounts.put(c, windowCounts.get(c) - 1);
              if (dictT.containsKey(c) && windowCounts.get(c).intValue() < dictT.get(c).intValue()) {
                  formed--;
              }

              // Move the left pointer ahead, this would help to look for a new window.
              l++;
          }

          // Keep expanding the window once we are done contracting.
          r++;   
      }

      return ans[0] == -1 ? "" : s.substring(ans[1], ans[2] + 1);
    }
   
	public static void main (String[] args) throws java.lang.Exception
	{
        Scanner inp = new Scanner(System.in);
        String s = inp.nextLine();
        String t = inp.nextLine();
        String res = minWindow(s,t);
        System.out.println(res.length());
    }
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not?