For this Question: Fashionable Integers are defined as those integers whose sum of digits is divisible by 2 and all of whose digits are odd. Given an integer N, find whether the given integer is fashionable or not.The first line of the input contains the length of the integer.
The second line contains the integer.

Constraints:
1 <= Length of Integer <= 10<sup>5</sup>Print "YES" if the given integer is fashionable, else print "NO".Sample Input:
2
73

Sample Output:
YES, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define int long long

signed main(){
    int n;
    cin >> n;
    string s;
    cin >> s;
    assert(n == s.size());
    int sum = 0;
    for(auto i : s){
        sum += (i - '0');
        if((i - '0') % 2 == 0){
            cout << "NO";
            return 0;
        }
    }
    if(sum % 2 == 0){
        cout << "YES";
    }
    else cout << "NO";
}, In this Programming Language: C++, Now tell me if this Code is compilable or not?