For this Question: Given an integer N, return the number of trailing zeroes in N!. 
Where N!=N*(N-1)*(N-2)....1Input contains a single integer N.

Constraints:-
1<= N <=1000000000000000Print the number of zeros in factorial(N)Sample Input
5

Sample Output
1

Explanation:-
5! = 120
number of zeroes = 1

Sample Input;
11

Sample output:
2, I have written this Solution Code: n=int(input())
divisible5count=0

while(n>0):
    divisible5count=divisible5count+n//5
    n=n//5

print(divisible5count), In this Programming Language: Python, Now tell me if this Code is compilable or not?