For this Question: You are given a positive integer N. Print "Yes" if N is a multiple of 3, otherwise, print "No".The input consists of a single integer N.

<b> Constraints: </b>
1 &le; N &le; 1000If N is a multiple of 3, print "Yes". Otherwise, print "No" (without the quotation marks). Note that the <b>output is case-sensitive</b>.Sample Input 1:
6

Sample Output 1:
Yes

Sample Input 2:
10

Sample Output 2:
No

(6 is a multiple of 3 (3*2==6) while 10 is not a multiple of 3), I have written this Solution Code: #include <bits/stdc++.h>
#define int long long
using namespace std;
 
#define FOR(i, a, b) for (int i = (a); i <= (b); i++)
 
 
 
signed main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
 
    int n;
    cin >> n;
    if (n % 3) cout << "No";
    else cout << "Yes";
}, In this Programming Language: C++, Now tell me if this Code is compilable or not?