For this Question: Given an integer array A[] of size N. For any subarray size i (1 <= i <= N), you have to do the following:
<ul><li>Write all subarrays of size i from array A on a piece of paper.</li><li>Now, replace each of these subarrays with their minimum element.</li><li>Now, find the maximum value among all these minimums.</li>
Print this maximum value for all subarray sizes k (1 <= k <= N).The first line contains an integer N denoting the size of the array. The second line contains N space-separated integers A1, A2, ..., AN denoting the elements of the array.

Constraint:-
1 <= N <= 10^5
1 <= A[i] <= 10^6Print the array of numbers of size N for each of the considered window size 1, 2, ..., N respectively.Sample Input: 
7
10 20 30 50 10 70 30

Sample Output: 
70 30 20 10 10 10 10 

Explanation:
Testcase 1:
First element in output indicates maximum of minimums of all windows of size 1. Minimums of windows of size 1 are {10}, {20}, {30}, {50}, {10}, {70} and {30}. Maximum of these minimums is 70.
Second element in output indicates maximum of minimums of all windows of size 2. Minimums of windows of size 2 are {10}, {20}, {30}, {10}, {10}, and {30}. Maximum of these minimums is 30.
Third element in output indicates maximum of minimums of all windows of size 3. Minimums of windows of size 3 are {10}, {20}, {10}, {10} and {10}. Maximum of these minimums is 20.
Similarly other elements of output are computed., I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
 
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
 
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;

int l[N], r[N], ans[N], a[N];

signed main() {
	IOS;
	int n;	cin >> n;
	stack<int> s;
	a[0] = a[n+1] = -inf;
	s.push(0);
	for(int i = 1; i <= n; i++){
		cin >> a[i];
		while(!s.empty() && a[s.top()] >= a[i])
			s.pop();
		l[i] = s.top();
		s.push(i);
	}	
	while(!s.empty())
		s.pop();
	s.push(n+1);
	for(int i = n; i >= 1; i--){
		while(!s.empty() && a[s.top()] >= a[i])
			s.pop();
		r[i] = s.top();
		s.push(i);
	}
	for(int i = 1; i <= n; i++){
		int len = r[i] - l[i] - 1;
		ans[len] = max(ans[len], a[i]);
	}
	for(int i = n-1; i >= 1; i--)
		ans[i] = max(ans[i], ans[i+1]);
	for(int i = 1; i <= n; i++)
		cout << ans[i] << " ";
	return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not?