For this Question: Uttu broke his phone. He can get it repaired by spending X rupees or he can buy a new phone by spending Y rupees. Uttu wants to spend as little money as possible. Find out if it is better to get the phone repaired or to buy a new phone.The first line contains a single integer T - the number of test cases. Then the test cases follow.
The first and only line of each test case contains two space- separated integers X and Y - the cost of getting the phone repaired and the cost of buying a new phone.

<b>Constraints</b>
1 ≤ T ≤ 1000
1 &le; X, Y &le; 10<sup>4</sup>For each test case,
- output REPAIR if it is better to get the phone repaired.
- output NEW PHONE if it is better to buy a new phone.
- output ANY if both the options have the same price.
You may print each character of REPAIR, NEW PHONE and ANY in uppercase.Sample Input
3
100 1000
10000 5000
3000 3000
Sample Output
REPAIR
NEW PHONE
ANY, I have written this Solution Code: #include <bits/stdc++.h>

using namespace std;

#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif

int32_t main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    auto start = std::chrono::high_resolution_clock::now();

    int tt;
    cin >> tt;
    while (tt--) {
        int x, y;
        cin >> x >> y;
        if (x > y) {
            cout << "NEW PHONE\n";
        } else if (y > x) {
            cout << "REPAIR\n";
        } else {
            cout << "ANY\n";
        }
    }

    auto stop = std::chrono::high_resolution_clock::now();
    auto duration = std::chrono::duration_cast<std::chrono::nanoseconds>(stop - start);
    cerr << "Time taken : " << ((long double)duration.count()) / ((long double)1e9) << "s " << endl;
    return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not?