For this Question: Find the last record of the dataset without limit or order by.
Print worker_id|first_name|last_name|salary|joining_date|department.DataFrame/SQL Table with the following schema -
<schema>[{'name': 'worker', 'columns': [{'name': 'worker_id', 'type': 'int64'}, {'name': 'first_name', 'type': 'object'}, {'name': 'last_name', 'type': 'object'}, {'name': 'salary', 'type': 'int64'}, {'name': 'joining_date', 'type': 'datetime64[ns]'}, {'name': 'department', 'type': 'object'}]}]</schema>Each row in a new line and each value of a row separated by a |, i.e.,
0|1|2
1|2|3
2|3|4-, I have written this Solution Code: SELECT *
FROM worker
WHERE worker_id =
    (SELECT DISTINCT last_value(worker_id) OVER ()
     FROM worker);, In this Programming Language: SQL, Now tell me if this Code is compilable or not?