For this Question: Given an integer N find number of positive integers with N digits  with all digits in non-decreasing order.  As this can be large find ans modulo 1000000007.
For example 111227 is valid whereas 1112231 is not.Input contains one line of input containing a single integer N.

1 <= N <= 1000000000000Print  a single integer containing the number of positive integers with N digits  with all digits in non-decreasing order modulo 1000000007.Sample Input
1

Sample output
9

Sample Input
2
 
Sample Input
45, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
 
#define ll long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
 
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;

int sz;
const int NN = 9;

class matrix{
public:
    ll mat[NN][NN];
    matrix(){
        for(int i = 0; i < NN; i++)
            for(int j = 0; j < NN; j++)
                mat[i][j] = 0;
        sz = NN;
    }
    inline matrix operator * (const matrix &a){
        matrix temp;
        for(int i = 0; i < sz; i++)
            for(int j = 0; j < sz; j++){
                for(int k = 0; k < sz; k++){
                temp.mat[i][j] += (mat[i][k] * a.mat[k][j]) % mod;
                if(temp.mat[i][j] >= mod)
                    temp.mat[i][j] -= mod;   
            }
        }
        return temp;
    }
    inline matrix operator + (const matrix &a){
        matrix temp;
        for(int i = 0; i < sz; i++)
            for(int j = 0; j < sz; j++){
                temp.mat[i][j] = mat[i][j] + a.mat[i][j] ;
                if(temp.mat[i][j] >= mod)
                    temp.mat[i][j] -= mod;
            }
        return temp;
    }
    inline matrix operator - (const matrix &a){
        matrix temp;
        for(int i = 0; i < sz; i++)
            for(int j = 0; j < sz; j++){
                temp.mat[i][j] = mat[i][j] - a.mat[i][j] ;
                if(temp.mat[i][j] < mod)
                    temp.mat[i][j] += mod;
            }
        return temp;
    }
    inline void operator = (const matrix &b){
        for(int i = 0; i < sz; i++)
            for(int j = 0; j < sz; j++)
                mat[i][j] = b.mat[i][j];
    }
    inline void print(){
        for(int i = 0; i < sz; i++){
            for(int j = 0; j < sz; j++){
                cout << mat[i][j] << " ";
            }
            cout << endl;
        }
    }
};

matrix pow(matrix a, ll k){
    matrix ans;
    for(int i = 0; i < sz; i++)
        ans.mat[i][i] = 1;
    while(k){
        if(k & 1)
            ans = ans * a;
        a = a * a;
        k >>= 1;
    }
    return ans;
}

signed main() {
	IOS;
	int n;	cin >> n;
	sz = 9;
	matrix a;
	for(int i = 0; i < sz; i++){
		for(int j = 0; j <= i; j++)
			a.mat[i][j] = 1;
	}
	a = pow(a, n);
	int ans = 0;
	for(int i = 0; i < sz; i++){
		ans += a.mat[i][0];
		ans %= mod;
	}
	cout << ans;
	return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not?