For this Question: Given a string S check if it is Pangram or not. A pangram is a sentence containing all 26 letters of the English Alphabet.First line of input contains of an integer T denoting number od test cases then T test cases follow. Each testcase contains a String S.

Constraints:
1 <= T <= 100
1 <= |S| <= 1000

Note:- String will not contain any spacesFor each test case print in a new line 1 if its a pangram else print 0.Input:
2
Bawdsjogflickquartzvenymph
sdfs

Output:
0
0

Explanation :
Testcase 1: In the given input, the letter 'x' of the english alphabet is not present. Hence, the output is 0.
Testcase 2: In the given input, there aren't all the letters present in the english alphabet. Hence, the output is 0., I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;

class Main
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner sc = new Scanner(System.in);
		int t = sc.nextInt();
while(t-->0){
		String s = sc.next();
int check = 1;
int p =0;
for(char ch = 'a';ch<='z';ch++){
p=0;
for(int i = 0;i<s.length();i++){
if(s.charAt(i)==ch){p=1;}
}
if(p==0){check=0;}
   }
   System.out.println(check);
}

	    

}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not?