For this Question: Given an array of N integers,. There are several right circular rotations of range [L. R] that you need to perform. After performing these rotations, you need to find element at a given index X.First line of input contains size of array N and the given index X.
The second line of input contains N space separated integers.
The third line contains number of ranges M for right circular rotations, next M lines contains two space space separated integers containing values of Li Ri.

Constrains:-
1 < = X < = N < = 100000
1 < = A[i] < = 100000
1 < = M < = 100000
1 < = L < = R < = NPrint the element present at the given X.Sample Input:-
5 2
1 2 3 4 5
2
1 3
1 4

Sample Output:-
3

Explanation:-
After first given rotation (1 3)
 arr[] = {3, 1, 2, 4, 5}
 After second rotation (1, 4) 
 arr[] = {4, 3, 1, 2, 5}
After all rotations we have element 3 at given index 2., I have written this Solution Code: import java.io.*;
import java.util.*;



class Main {
    static class Reader {
        final private int BUFFER_SIZE = 1 << 16;
        private DataInputStream din;
        private byte[] buffer;
        private int bufferPointer, bytesRead;

        public Reader()
        {
            din = new DataInputStream(System.in);
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public Reader(String file_name) throws IOException
        {
            din = new DataInputStream(
                new FileInputStream(file_name));
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public String readLine() throws IOException
        {
            byte[] buf = new byte[64];
            int cnt = 0, c;
            while ((c = read()) != -1) {
                if (c == '\n') {
                    if (cnt != 0) {
                        break;
                    }
                    else {
                        continue;
                    }
                }
                buf[cnt++] = (byte)c;
            }
            return new String(buf, 0, cnt);
        }

        public int nextInt() throws IOException
        {
            int ret = 0;
            byte c = read();
            while (c <= ' ') {
                c = read();
            }
            boolean neg = (c == '-');
            if (neg)
                c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (neg)
                return -ret;
            return ret;
        }

        public long nextLong() throws IOException
        {
            long ret = 0;
            byte c = read();
            while (c <= ' ')
                c = read();
            boolean neg = (c == '-');
            if (neg)
                c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (neg)
                return -ret;
            return ret;
        }

        public double nextDouble() throws IOException
        {
            double ret = 0, div = 1;
            byte c = read();
            while (c <= ' ')
                c = read();
            boolean neg = (c == '-');
            if (neg)
                c = read();

            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (c == '.') {
                while ((c = read()) >= '0' && c <= '9') {
                    ret += (c - '0') / (div *= 10);
                }
            }

            if (neg)
                return -ret;
            return ret;
        }

        private void fillBuffer() throws IOException
        {
            bytesRead = din.read(buffer, bufferPointer = 0,
                                 BUFFER_SIZE);
            if (bytesRead == -1)
                buffer[0] = -1;
        }

        private byte read() throws IOException
        {
            if (bufferPointer == bytesRead)
                fillBuffer();
            return buffer[bufferPointer++];
        }

        public void close() throws IOException
        {
            if (din == null)
                return;
            din.close();
        }
    }
    static void rotation(int[] arr,int l,int r){
        int temp=arr[r];
        for(int i=r;i>l;i--){
            arr[i]=arr[i-1];
        }
        arr[l]=temp;
    }

    public static void main (String[] args) throws IOException{
    Reader sc = new Reader();
    int n=sc.nextInt();
    int x=sc.nextInt();
    int[] arr=new int[n];
    for(int i=0;i<n;i++)
        arr[i]=sc.nextInt();
    int M=sc.nextInt();
    while(M-->0){
       int Li=sc.nextInt();
       int Ri=sc.nextInt();
        rotation(arr,Li-1,Ri-1);
    }
        System.out.println(arr[x-1]);
    }
}, In this Programming Language: Java, Now tell me if this Code is compilable or not?