For this Question: A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
 1) S is a palindrome.
 2) Let N be the length of S. The string formed by the 1- st through ((N−1)/2)<sub>th</sub>  characters of S is a palindrome.
 3) The string consisting of the (N+3)/2- st through N<sub>th</sub> characters of S is a palindrome.
Determine whether S is a strong palindrome.The first and the only line of the input contains a single string S.

<b>Constraints:</b>
3 &le; |S| &le; 99If S is a strong palindrome, print "Yes"; otherwise, print "No".<b>Sample Input 1:</b>
akasaka

<b>Sample Output 1:</b>
Yes

<b>Sample Explanation 1:</b>
1) S is Akasaka.
2) The string formed by the 1<sub>st</sub> through the 3<sub>rd</sub> characters is aka.
3) The string formed by the 5<sub>th</sub> through the 7<sub>th</sub> characters is aka. All of these are palindromes, so S is a strong palindrome., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define pi    acos(-1.0)
#define mod   1000000007
#define endl  '\n'
#define ha    cout<<"YES"<<endl
#define na    cout<<"NO"<<endl
#define mod   1000000007
#define ll    long long
int main()
{
    string s;
    cin >> s;
    int f=0,fl=0,flag=0;
    int l=s.length();//7
   for(int i=0,j=l-1;i<l/2;i++,j--)
    {
        if(s[i]!=s[j])
        {
            f=1;
            break;
        }

   }
   for(int i=0,j=l/2-1;i<l/2;i++,j--)
   {
    if(s[i]!=s[j])
    {
        fl=1;
        break;
    }
   }
for(int i=l/2+1,j=l-1;i<j;i++,j--)
{
    if(s[i]!=s[j])
    {
        flag=1;
        break;
    }
}





//cout<<f<<fl<<flag<<endl;
 
 if (f == 0 && fl==0 && flag==0) cout<<"Yes";
 else cout<<"No";
} , In this Programming Language: C++, Now tell me if this Code is compilable or not?