For this Question: You are given 3 non-negative integers A, B and C. In one operation, you can pick any two of the given integers and subtract one from both of them.

If it is possible to make all the 3 integers zero after some number of operations (possibly none), print "Yes". Otherwise, print "No".The first line contains a single integer T – the number of test cases.
Each of the next T lines contains 3 space separated integers A, B and C respectively.

<b> Constraints: </b>
1 ≤ T ≤ 10
0 ≤ A, B, C ≤ 10Output T lines, the i<sup>th</sup> line containing a single word, either "Yes" or "No" – the answer to the i<sup>th</sup> test case.Sample Input 1:
2
3 4 2
2 2 2

Sample Output 1:
No
Yes

Sample Explanation 1:
For the first test case, there is no possible way to make all the elements zero.
For the second test case, we can pick elements in the following order: (A,B), (B,C), (A,C), I have written this Solution Code: 

// #pragma GCC optimize("Ofast")
// #pragma GCC target("avx,avx2,fma")
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
#define pi 3.141592653589793238
#define int long long
#define ll long long
#define ld long double
using namespace __gnu_pbds;
using namespace std;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rnd(chrono::high_resolution_clock::now().time_since_epoch().count());


long long powm(long long a, long long b,long long mod) {
long long res = 1;
while (b > 0) {
    if (b & 1)
        res = res * a %mod;
    a = a * a %mod;
    b >>= 1;
}

return res;
}

ll gcd(ll a, ll b)
{
if (b == 0)
    return a;
return gcd(b, a % b);      
}






signed main()
{

ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(0);


#ifndef ONLINE_JUDGE
if(fopen("input.txt","r"))
{
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
}
#endif
    
    
    int t;
    cin>>t;
    while(t--)
    {
        int a,b,c;
        cin>>a>>b>>c;

        if(a>b+c||b>a+c||c>a+b)
            cout<<"No\n";
        else
        {
            int sum=a+b+c;
            if(sum%2)
                cout<<"No\n";
            else
                cout<<"Yes\n";
        }        
    }



    
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not?