For this Question: You are given a string S of length N consisting of lowercase characters 'a' and 'b'. In one operation, you can select a character and make it equal to one of its adjacent characters. For example, if S = "aab", in one operation you can convert it to any of the following:

1. "aab": By changing the 1<sup>st</sup> character to the 2<sup>nd</sup> character.
2. "aab": By changing the 2<sup>nd</sup> character to the 1<sup>st</sup> character.
3. "abb": By changing the 2<sup>nd</sup> character to the 3<sup>rd</sup> character.
4. "aaa": By changing the 3<sup>rd</sup> character to the 2<sup>nd</sup> character.

Find the minimum number of operations to make all the characters in the string equal.The first line of the input contains a single integer N.
The second line contains a string S of length N consisting of only 'a' and 'b'.

<b> Constraints: </b>
1 ≤ N ≤ 5000Print the minimum number of operations to make all the characters in the string equal.Sample Input 1:
4
abaa

Sample Output 1:
1

Sample Explanation 1:
You can replace the 'b' at the second position by the 'a' at the first position. Now the string becomes "aaaa". 

Sample Input 2:
5
bbbaa

Sample Output 2:
2

, I have written this Solution Code: //Author: Xzirium
//Time and Date: 03:04:29  27 December 2021
 
//Optional FAST
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native")
 
//Required Libraries
 
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/detail/standard_policies.hpp>
 
//Required namespaces
 
using namespace std;
using namespace __gnu_pbds;
 
//Required defines
 
#define endl '\n'
 
#define READ(X) cin>>X;
#define READV(X) long long X; cin>>X;
#define READAR(A,N) long long A[N]; for(long long i=0;i<N;i++) {cin>>A[i];}
#define rz(A,N) A.resize(N);
#define sz(X) (long long)(X.size())
#define pb push_back
#define pf push_front
#define fi first
#define se second
#define FORI(a,b,c) for(long long a=b;a<c;a++)
#define FORD(a,b,c) for(long long a=b;a>c;a--)
 
//Required typedefs
 
template <typename T> using ordered_set = tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;
template <typename T> using ordered_set1 = tree<T,null_type,greater<T>,rb_tree_tag,tree_order_statistics_node_update>;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<long long,long long> pll;
 
//Required Constants
 
const long long inf=(long long)1e18;
const long long MOD=(long long)(1e9+7);
const long long INIT=(long long)(1e6+1);
const long double PI=3.14159265358979;
 
// Required random number generators
 
// mt19937 gen_rand_int(chrono::steady_clock::now().time_since_epoch().count());
// mt19937_64 gen_rand_ll(chrono::steady_clock::now().time_since_epoch().count());
 
//Required Functions
 
ll power(ll b, ll e)
{
    ll r = 1ll;
    for(; e > 0; e /= 2, (b *= b) %= MOD)
        if(e % 2) (r *= b) %= MOD;
    return r;
}
ll modInverse(ll a) 
{ 
   return power(a,MOD-2); 
   
}
 
//Work
 
int main()
{
    #ifndef ONLINE_JUDGE
    if (fopen("INPUT.txt", "r"))
    {
        freopen ("INPUT.txt" , "r" , stdin);
        //freopen ("OUTPUT.txt" , "w" , stdout);
    }
    #endif
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
 
    clock_t clk;
    clk = clock();
//-----------------------------------------------------------------------------------------------------------//
 
    READV(N);
    string S;
    cin>>S;
    ll a=0,b=0;
    FORI(i,0,N)
    {
        if(S[i]=='a')
        {
            a++;
        }
        else
        {
            b++;
        }
    }
    cout<<min(a,b)<<endl;
 
//-----------------------------------------------------------------------------------------------------------//
 
 
    clk = clock() - clk;
    cerr << fixed << setprecision(6) << "Time: " << ((double)clk)/CLOCKS_PER_SEC << endl;
 
    return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not?