For this Question: Given an integer N. Find the number of divisors of N factorial. 
As answer can be huge find answer modulo 1000000007.The only line of input contains a single integer N.

1 <= N <= 1000Print the number of the positive divisors of N! modulo 1000000007Sample Input 1 
3

Sample Output 1 
4

There are four divisors of 3!  = 6: 1, 2, 3 and 6 .Thus, the output should be 4

Sample Input 2 
6

Sample Output 2 
30, I have written this Solution Code: allPrimes = [];  
  
def sieve(n):  
  
    prime = [True] * (n + 1);  
  
    p = 2; 
    while(p * p <= n): 
          
        if (prime[p] == True): 
              
            i = p * 2; 
            while(i <= n):  
                prime[i] = False; 
                i += p; 
        p += 1;  
  
    for p in range(2, n + 1):  
        if (prime[p]):  
            allPrimes.append(p); 
  
def factorialDivisors(n): 
  
    sieve(n); # create sieve  
  
    result = 1;  
  
    for i in range(len(allPrimes)):  
          
        p = allPrimes[i];  
  
        exp = 0;  
        while (p <= n): 
            exp = exp + int(n / p);  
            p = p * allPrimes[i];  
  
        result = result * (exp + 1);  
  
    return result%1000000007;  
  
n=int(input())
print(factorialDivisors(n));, In this Programming Language: Python, Now tell me if this Code is compilable or not?