For this Question: Given an integer N, consisting of digits from 1 to 9. You can break the number by adding '+' in between, your have to find the sum of all the numbers that can be formed through this way.
For eg:- N = 256
256 = 256
25 + 6 = 31
2 + 56 = 58
2 + 5 + 6 = 13
sum = 256 + 31 + 58 + 13 = 358The input contains a single integer N.

Constraints:-
1 <= N <= 999999999Print the sum of all the possible numbers.Sample Input:
256

Sample Output:
358

Sample Input:
125

Sample Output:
176, I have written this Solution Code: #include <bits/stdc++.h>
#define uint unsigned int
#define ll long long
#define ull unsigned long long
#define sqr(a) (1LL * (a) * (a))
#define mt(...) " [" << #__VA_ARGS__ << ": " << __VA_ARGS__ << "] "
using namespace std;
const int mod = 1000000007;
const int INF = 0x3f3f3f3f;
 
const int N = 10;
ll res = 0;
 
void solve(string &str, int n, int i, ll s, ll last) {
    if (i == n) {
        res += s;
        // cout << mt(s) << '\n';
        return;
    }
    int curr = str[i] - '0';
    solve(str, n, i + 1, s + curr, curr);
    solve(str, n, i + 1, s - last + last * 10 + curr, last * 10 + curr);
}
int main() {
    ios::sync_with_stdio(false); cin.tie(NULL);
    // freopen("input.txt", "r", stdin);
    // freopen("output.txt", "w", stdout);
    string str;
    cin >> str;
    int n = str.size();
    // solve(str, n, 1, str[0] - '0', str[0] - '0');
    // cout << res << '\n';
    ll res = 0;
    int maxbit = 1 << n;
    for (int mask = 0; mask < maxbit; ++mask) {
        ll prev = 0;
        ll sum = 0;
        for (int t = 0; t < n; ++t) {
            if (mask & (1 << t)) {
                sum -= prev;
                prev = prev * 10 + (str[t] - '0');
                sum += prev;
            }
            else {
                prev = str[t] - '0';
                sum += prev;
            }
        }
        res += sum;
    }
    res /= 2;
    cout << res << '\n';
 
    return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not?