For this Question: Shinchan and Kazama are standing in a horizontal line, Shinchan is standing at point A and Kazama is standing at point B. Kazama is very intelligent and recently he learned how to calculate the speed if the distance and time are given and now he wants to check if the formula he learned is correct or not So he starts running at a speed of S unit/s towards Shinhan and noted the time he reaches to Shinhan. Since Kazama is disturbed by Shinchan, can you calculate the time for him?<b>User Task:</b>
Complete the function <b>Time()</b> that takes integers A, B, and S as parameters.

<b>Constraints:-</b>
1 <= A, B, V <= 1000

<b>Note:-</b>
It is guaranteed that the calculated distance will always be divisible by V.Return the Time taken in seconds by Kazama to reach Shin-chan.

<b>Note:-</b> 
Remember Distance can not be negativeSample Input:-
A = 5, B = 2, S = 3

Sample Output:-
 1

Sample Input:-
A = 9, B = 1, S = 2

Sample Output:-
4

<b>Explanation 1:-</b>
Distance = 5-2 = 3, Speed = 3
Time = Distance/Speed
, I have written this Solution Code: #include <bits/stdc++.h>

using namespace std;

#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif

int Time(int a, int b, int s) {
    return (abs(a - b) / s);
}

int main() {
    int n, m, k;
    cin >> n >> m >> k;
    cout << Time(n, m, k) << "\n";
    return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not?