For this Question: Jerry is having yet another existential crisis. In order to keep him occupied Rick gives him a task.

F(N, K) = The position (1-indexed) of K when numbers from 1 to N are lexicographically sorted.
For example if N = 11, the lexicographically sorted order will be:
1, 10, 11, 2, 3, 4, 5, 6, 7, 8, 9. So F(11, 2) = 4, as 2 is in the 4th position.

Given K and M, find the smallest N such that F(N, K) = M.Input contains two integers K and M.

Constraints:
1 <= K, M <= 1000000000Output smallest N such that F(N, K)=M and if no such N exists print 0.Sample Input 1
2 4

Sample Output 1
11

Sample Input 2
2 1

Sample Output 2
0, I have written this Solution Code: def dfs(n, k, c, j = 0):
    if k == 0: return c
    
    base = int("1" * len(n))
    for i in range(j, 10):
        new = int(c + str(i))
        t = 0
        if str(i) == n[0] and len(n) > 1:
            t += int(str(n)[1:]) + 1
            base //= 10
        t+= base
        
        if t >= k:
            return dfs(str(base * 9 // 10) if str(i) != n[0] else n[1:], k - 1, c + str(i))
        k -= t
def findKthNumber(n, k):
    return dfs(str(n), k, "", 1)

k, m = map(int, input().split())
s = k
e = 1000000000000000000
val = 0
s1 = str(k)
while(s <= e):
    mid = (s+e)//2
    s2 = str(findKthNumber(mid, m))
    if(s1 == s2):
        val = mid
        e = mid-1
    elif(s1 > s2):
        e = mid-1
    else:
        s = mid+1
print(val), In this Programming Language: Python, Now tell me if this Code is compilable or not?